Index exceeds matrix dimensions.AGAIN

FAILED AGAIN ;-(((( Accepted wrong one

 dU(35)=55;
f = figure('Position',[10 10 600 600]);
dat = {-1,1,1;0,-1,0;0,0,-1;1,0,0};
cnames = {'18','29','51'};
rnames = {'12','26','35','44'};
t = uitable('Parent',f,'Data',dat,'ColumnName',cnames,... 
            'RowName',rnames,'Position',[10 10 590 590]);
        blnA = logical( A == -1 );
blnOut = find(any(A == -1,2));
maxValue = max(negcolumn)
index = rnames{maxValue}
dU(tzan)

maxValue =

     3
index =

35

Index exceeds matrix dimensions.

Please give me easy way...

Help, Help, Help It is my last question?

[Light]

I don't need vector form. I just need regular number

it must be

dU(tzan)=55

But it is error

Index exceeds matrix dimensions.

[Light]

dU(35)=59;

t=35;

dU(t)

ans =

    59

t=index

t =

35

>> dU(t)

""""Index exceeds matrix dimensions.""""

Don't make me cry ;-(

[Image Analyst]

Please stop posting the question over and over again. Learn how to use the debugger: http://blogs.mathworks.com/videos/2012/07/03/debugging-in-matlab/. It will solve all your problems. It really will. We can't help you because we don't know what A is. Put a "clear all" at the beginning of your code and get rid of that pre-existing A. You will find your code crashes when it tries to access A. Then proceed to fix your code using the debugger.

[Light]

Sorry i'm nervous. I will change it clear!

[Image Analyst]

No one even knows what you want to do. The code is so bad that we can't even figure it out. Please explain, in words, what you want to do with the cnames and rnames and the table. It seems like you're looking for -1's but I don't know what you want to do if you find them.

[Azzi Abdelmalek]

Light, can you enlighten us by making your question breve and clear, or maybe you need to learn basics of Matlab