Partition of a set.

7 vues (au cours des 30 derniers jours)
rohini more
rohini more le 30 Mar 2021
Commenté : rohini more le 6 Avr 2021
consider a partition of X= with where denotes the union of disjoint sets.
Remark that ,
I would like to implement the matlab code for above partition.
Please help me .
Thanks in advance.
  3 commentaires
rohini more
rohini more le 30 Mar 2021
Let n=7, L=4
If I split n is following way
n=1+2+3+1 according to that [n]={1}
rohini more
rohini more le 30 Mar 2021
Input is n=7 and L=4
Output should be
n=1+2+3+1, [n]=
where h1=1,h2=2 ,h3=3,h4=1 and H1={1},H2={2,3}, H3={4,5,6},H4={7}

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Bruno Luong
Bruno Luong le 30 Mar 2021
Modifié(e) : Bruno Luong le 30 Mar 2021
>> N=5; L=3;
>> h=allVL1(L,N-L)+1;
>> H=arrayfun(@(r) mat2cell(1:N,1,h(r,:)),(1:size(h,1))','unif',false);
>> DispPartObj(H) % FEX in my other answer
The 6 partition(s) are:
{1} {2} {3 4 5}
{1} {2 3} {4 5}
{1} {2 3 4} {5}
{1 2} {3} {4 5}
{1 2} {3 4} {5}
{1 2 3} {4} {5}
  2 commentaires
rohini more
rohini more le 30 Mar 2021
Okay.
Thank you very much.
rohini more
rohini more le 6 Avr 2021
Suppose I would like to consider random partition of set what changes I have to do in this code.
Thanks in advance.

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Plus de réponses (1)

Bruno Luong
Bruno Luong le 30 Mar 2021
Modifié(e) : Bruno Luong le 30 Mar 2021
>> N=5; L=3;
>> DispPartObj(SetPartition(N,L))
The 25 partition(s) are:
{1 2 3} {4} {5}
{1 2 4} {3} {5}
{1 2} {3 4} {5}
{1 3 4} {2} {5}
{1 3} {2 4} {5}
{1 4} {2 3} {5}
{1} {2 3 4} {5}
{1 2 5} {3} {4}
{1 2} {3 5} {4}
{1 2} {3} {4 5}
{1 3 5} {2} {4}
{1 3} {2 5} {4}
{1 3} {2} {4 5}
{1 5} {2 3} {4}
{1} {2 3 5} {4}
{1} {2 3} {4 5}
{1 4 5} {2} {3}
{1 4} {2 5} {3}
{1 4} {2} {3 5}
{1 5} {2 4} {3}
{1} {2 4 5} {3}
{1} {2 4} {3 5}
{1 5} {2} {3 4}
{1} {2 5} {3 4}
{1} {2} {3 4 5}
  1 commentaire
rohini more
rohini more le 31 Mar 2021
Okay.
Thank you.

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