Simple Question about Optimization of a FOR loop

1 vue (au cours des 30 derniers jours)
Mohsen
Mohsen le 14 Juin 2013
How can I optimize (vectorize?) the following code in order to avoid the for loop and make the code to run faster?
for i=1:55;
A(i)=B((i-1)*3+1,1);
end
A is 1 x 55 and B is 165 x 1
Many thanks!
  3 commentaires
Laila Kazemi
Laila Kazemi le 14 Juin 2013
bc ur only assigning one raw to A
Mohsen
Mohsen le 14 Juin 2013
You are both right!
A is 1 x 55
Do you know how to optimize the for loop? Thanks!

Connectez-vous pour commenter.

Réponses (2)

Laila Kazemi
Laila Kazemi le 14 Juin 2013
C= B*3 +1 A (1:55, 1:55)= C(1:55, 1)
but the dimensions of ur matrices dont match , if B was 55 by 1 , it would have worked
  3 commentaires
Laila Kazemi
Laila Kazemi le 14 Juin 2013
actaully instead one make a matrix called D with D( , 1:165)=(1)
Mohsen
Mohsen le 16 Juin 2013
Thanks for your answer but it doesn't seem to be the right answer... Please note that the multiplication by 3 and the addition by 1 is used to access the content of each element and not to modify the content of the elements...
I found this answer and it worked:
A=B(1:3:55*3,1);
Thanks again.

Connectez-vous pour commenter.


Andrei Bobrov
Andrei Bobrov le 14 Juin 2013
A(1,:) = B((0:size(A,2)-1)*3+1);
  1 commentaire
Mohsen
Mohsen le 16 Juin 2013
Thanks for your answer but it doesn't seem to be the right answer...
I found this answer and it worked:
A=B(1:3:55*3,1);
Thanks again.

Connectez-vous pour commenter.

Catégories

En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange

Produits

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by