Strings with changing length and cases

Hi, Im trying to make the following code work and it just wont seem to do what I want. NOTE - The string length of my variable is changing so for different cases I want a different interval.
Astr = '123456789'
switch Astr
case strcmp(Astr([2:4,5:7]), '234567' )
x = 5
case strcmp(Astr([3:6,6:8]), '789123' )
x = 6
case strcmp(Astr([1:3,4:6]), '912345' )
x = 7
otherwise
x = 8
end
I think it has to do with the way Im defining the string values, it keeps outputting x = 8 (the otherwise case). Please let me know how to fix thanks!

 Réponse acceptée

Azzi Abdelmalek
Azzi Abdelmalek le 19 Juin 2013
It's more appropriate to use IF statement
Astr = '123456789'
if isequal(Astr([2:4,5:7]), '234567' )
x = 5
elseif isequal(Astr([3:6,6:8]), '789123' )
x = 6
elseif isequal(Astr([1:3,4:6]), '912345' )
x = 7
else
x = 8
end

Plus de réponses (2)

Iain
Iain le 19 Juin 2013

0 votes

Assuming that you've shown us "everything". Theres a better way:
x = 8 - (Astr(3) == '2') - 2*(Astr(3) == '7') - 3*(Astr(3) == '3');

2 commentaires

JP
JP le 19 Juin 2013
Well I havent shown everything...I was just using this as a simpler example for a more complex code Im working on....
Iain
Iain le 19 Juin 2013
Azzi's solution is correct, but it will be easy to get lost in it, and make logical errors.

Connectez-vous pour commenter.

Jan
Jan le 19 Juin 2013
This case can never happen:
strcmp(Astr([3:6,6:8]), '789123' )
One string has 7 character with a repeated sixth element, while the other string has 6 characters only without a repetition.

Catégories

En savoir plus sur Characters and Strings dans Centre d'aide et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by