Matrix construction over a loop

4 views (last 30 days)
ASHA RANI on 11 Apr 2021
Commented: ASHA RANI on 12 Apr 2021
x=[1:1:10];
a=2;
b=4;
c=6;
for i=1:length(x)
A=a*b/x(i);
B=c+A(i)/b;
D=a+b;
E=1-2*c;
MAT=[B(i);D;E];
M=sqrt([MAT])
end
I am not able to matrix corresponding to 10 values of x.
plz help
thanks
David Fletcher on 11 Apr 2021
This line will create a scaler value for A
A=a*b/x(i);
On the following line you are trying to index a scaler value
B=c+A(i)/b;

VBBV on 11 Apr 2021
clear
x=[1:1:10];
a=2;
b=4;
c=6;
for i=1:length(x)
A(i)=a*b/x(i);
B(i)=c+A(i)/b;
D=a+b;
E=1-2*c;
MAT(i,:)=[B(i);D;E];
end
M=sqrt(abs(MAT))
ASHA RANI on 12 Apr 2021
VBBV, thanks
Its works .

Jan on 11 Apr 2021
Maybe you want:
for i = 1:length(x)
A(i) = a * b / x(i);
B(i) = c + A(i) / b;
D(i) = a + b;
E(i) = 1 - 2 * c;
...

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