fopen problem help please
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In this part of code
disp(filename)
fid=fopen([filename '.hea']);
disp('debug')
I have error
---WFDB/I0005 ->(its a display filename, i have in WFDB folder files I0005.hea and i0005.mat)
---Error using fopen
---First input must be a file name or a file identifier.
Please, help with fopen) (m2020 mac version)
2 commentaires
Stephen23
le 15 Avr 2021
@Anton Gubrienko: please show the complete error message. This means all of the red text.
Walter Roberson
le 15 Avr 2021
I suspect that your filename variable is a cell array instead of a character vector or string scalar
Réponses (1)
Ankriti Sachan
le 20 Avr 2021
As Walter mentioned, I am also guessing that you are providing a folder name instead of a filename as the input to the fopen function. Please verify the same. Also, you can verify if any other file in the same folder is accessible using fopen.
Also, if you are trying to read the physionet data, please refer to the answer here - https://in.mathworks.com/matlabcentral/answers/528018-how-can-i-create-a-vector-from-one-specific-data-in-552-hea-files-in-matlab.
I hope this answers your query.
4 commentaires
Walter Roberson
le 20 Avr 2021
First input must be a file name or a file identifier
You do not get that message if you accidentally name a directory instead of a file.
mkdir junk_dir_for_test
[fid, msg] = fopen('junk_dir_for_test');
if fid < 0
warning('failed to open file because: "%s', msg);
else
fprintf('fopen of directory worked?\n');
fclose(fid)
end
[fid, msg] = fopen('junk_does_not_exist_for_test');
if fid < 0
warning('failed to open file because: "%s', msg);
else
fprintf('fopen of non-existent file worked?\n');
fclose(fid)
end
[fid, msg] = fopen({'junk_does_not_exist_for_test'});
if fid < 0
warning('failed to open file named as cell because: "%s', msg);
else
fprintf('fopen of non-existent named as cell file worked?\n');
fclose(fid)
end
The only case you get the error message being observed is if the parameter passed to fopen() is not a character vector or string scalar.
In the context of
% fid=fopen([filename '.hea']);
then if filename were a cell array of character vectors instead of a character vector, you would get that problem.
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