Function definition using a variable from a block based on a for loop

4 vues (au cours des 30 derniers jours)
Hi!
I would like to create a function in which the definition changes according to a for loop.
I have 2 row vectors from which I want to use values:
A=[1 2 3 4 5 6 7 8 9 10]
Att=[0 2 4 6 8 10 12 14 16 18]
An example:
function [a]=myf(Att)
a=Att(ii)*A(ii);
end
I would like to use the first elements of A and Att in the first cycle then the second and so on. My real function is a bit more complicated, my question is how can I change the variable inside the function according to a for loop.
Thank you!
  1 commentaire
Gábor Dupák
Gábor Dupák le 22 Avr 2021
Oh and I know that it can be solved without using a function, but I MUST use a function ! :)

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Réponse acceptée

Steven Lord
Steven Lord le 22 Avr 2021
For this I'd use one of two approaches.
A=[1 2 3 4 5 6 7 8 9 10];
Att=[0 2 4 6 8 10 12 14 16 18];
% Approach 1
y = myf1(Att, A);
for k = 1:numel(Att)
fprintf("Element %d of the result is %d\n", k, y(k))
end
Element 1 of the result is 0 Element 2 of the result is 4 Element 3 of the result is 12 Element 4 of the result is 24 Element 5 of the result is 40 Element 6 of the result is 60 Element 7 of the result is 84 Element 8 of the result is 112 Element 9 of the result is 144 Element 10 of the result is 180
% Approach 2
for k = 1:numel(Att)
y = myf2(Att, A, k);
fprintf("Element %d of the result is %d\n", k, y)
end
Element 1 of the result is 0 Element 2 of the result is 4 Element 3 of the result is 12 Element 4 of the result is 24 Element 5 of the result is 40 Element 6 of the result is 60 Element 7 of the result is 84 Element 8 of the result is 112 Element 9 of the result is 144 Element 10 of the result is 180
function a=myf1(Att, A)
a=Att.*A;
end
function a=myf2(Att, A, ii)
a=Att(ii)*A(ii);
end
  2 commentaires
Gábor Dupák
Gábor Dupák le 22 Avr 2021
Thank you! And how I can store the results in a row vector? It would be very helpful for me :)
Gábor Dupák
Gábor Dupák le 22 Avr 2021
Oh I solved it ! Your help was awesome !

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