Hello everybody. Here is the issue.. having the array C{1,1} I normally don’t know the exact number of rows. How can I split that matrix in 2 parts?, I can use :
o = (C{1,1}(:,[1:end/2]));
to split the first part, however the second part is not that easy because the number of rows varies at the interior in each ‘C’ array. Thank you.

 Réponse acceptée

Jan
Jan le 23 Avr 2021
Modifié(e) : Jan le 23 Avr 2021

0 votes

Data = C{1,1};
Len = size(Data, 2);
Half = floor(Len / 2);
Part1 = Data(:, 1:Half);
Part2 = Data(:, Half+1:Len);
It is not clear to me, what this means: "second part is not that easy because the number of rows varies at the interior in each ‘C’ array"
By the way, 1:x is a vector already. The square brackets are Matlab concatenation operator. [1:x] concatenates 1:x with nothing and is a waste of time in consequence.

6 commentaires

Fercho_Sala
Fercho_Sala le 24 Avr 2021
@Jan thank you so much, this is the right answer :)
Fercho_Sala
Fercho_Sala le 24 Avr 2021
@Jan how I can use the same code to split the following arrays C{1,2},C{1,3} ... etc with the same structure (Part1, Part2) for each one independently? , probably with a loop? Thanks.
Jan
Jan le 25 Avr 2021
Yes, a loop will solve this:
C1 = cell(size(C));
C2 = cell(size(C));
for k = 1:numel(C)
Data = C{1, k};
Len = size(Data, 2);
Half = floor(Len / 2);
C1{k} = Data(:, 1:Half);
C2{k} = Data(:, Half+1:Len);
end
Fercho_Sala
Fercho_Sala le 26 Avr 2021
@Jan thanks a lot for your knowledge , it works pretty good. :)
Fercho_Sala
Fercho_Sala le 26 Avr 2021
Modifié(e) : Fercho_Sala le 26 Avr 2021
@Jan is it possible to plot each item within 'C1' or 'C2' in a subplot structure (4x4) (of course it will be several independent windows) using the 'imagesc' function with the same loop structure? if so, how could you do it?
Fercho_Sala
Fercho_Sala le 26 Avr 2021
@Jan any comments?

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