fill in zeros in a matrix

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Mate 2u
Mate 2u le 9 Juil 2013
Hi all, I have a 1000x1 double matrix. It is full of numbers....but on some situations I get multiple 0s.
Whenever I encounter 0's, I want to fill the zeros with the average of the two numbers (the nearest non zero numbers above and below).
For example, if we had 3, 4, 0 ,3 , 2, 2, 0 ,0, 0, 3, 2, 1
we would get 3, 4, 3.5, 3, 2, 2, 2.5, 2.5, 2.5, 3, 2, 1.
The shorter and faster the code, the better....please remember the amount of consecutive zeros vary.

Réponse acceptée

Jan
Jan le 10 Juil 2013
x = [3, 4, 0 ,3 , 2, 2, 0 ,0, 0, 3, 2, 1];
m = (x == 0);
x(m) = interp1(find(~m), x(~m), find(m));

Plus de réponses (1)

Matt J
Matt J le 9 Juil 2013
I would recommend replacing the zeros with NaNs and using something like this,
instead.
  1 commentaire
Mate 2u
Mate 2u le 9 Juil 2013
Hi, looking for something much shorter and easier to implement, as it was a interview question....and would be nice to have something short which I can remember.

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