Drawing upside down cone using spherical coordinates.
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Viktor Karlsson
le 30 Avr 2021
Commenté : Viktor Karlsson
le 3 Mai 2021
I wrote the following code:
phi=pi/6;
theta=linspace(0,2*pi,63); %Theta goes from 0 to 2*pi.
a=linspace(0,1,21);
[PHI,THETA,A]=meshgrid(phi,theta,a);
X=A.*sin(PHI).*cos(THETA); % Spherical coordinates
Y=A.*sin(PHI).*sin(THETA);
Z=A.*cos(PHI);
surf(X,Y,Z)
axis equal
It won't draw, but instead gives me an empty 2D graph.
The error message is:
Error using matlab.graphics.chart.primitive.Surface
Value must be a vector or 2D array of numeric type.
hh = matlab.graphics.chart.primitive.Surface(allargs{:});
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Benjamin Kraus
le 30 Avr 2021
The issue you are facing is that when you call meshgrid you are specifying three input vectors, so the output matrices are going to be 3D matrices, but surf only accepts 2D matrices.
My recommendation is to remove phi from the call to meshgrid:
phi=pi/6;
theta=linspace(0,2*pi,63);
a=linspace(0,1,21);
[THETA,A]=meshgrid(theta,a);
X=A.*sin(phi).*cos(THETA);
Y=A.*sin(phi).*sin(THETA);
Z=A.*cos(phi);
surf(X,Y,Z)
axis equal
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