How can i reshape the code as below

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Kaavya N
Kaavya N le 2 Mai 2021
Commenté : Kaavya N le 3 Mai 2021
k=[dec2hex(floor(rand * 2 ^ 96),24),dec2hex(floor(rand * 2 ^ 96),24), dec2hex(floor(rand * 2^ 64),16)];
%k generates random 64 characters
%k = 0924668B8FB8700000000000D96089C6C815880000000000EF1A2E75CDB28000
w=reshape(k,4,[ ]);
%w gives 4x16 char array
% '068700D8C800E2C8'
%'96F000998800FED0'
%'28B0006C100017B0'
%'4B8000065000A520'
how can I group 2 characters as one element and make w a 4x8 matrix like
09 8F ....................
24 B8 .....................
66 .........................
8B ...........................
  2 commentaires
Image Analyst
Image Analyst le 2 Mai 2021
What is "key"?
Kaavya N
Kaavya N le 2 Mai 2021
sorry its k

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Réponse acceptée

DGM
DGM le 3 Mai 2021
Try this:
k = '0924668B8FB8700000000000D96089C6C815880000000000EF1A2E75CDB28000'
wo = reshape(k(1:2:end),4,[]);
we = reshape(k(2:2:end),4,[]);
w = reshape([wo; we],4,[])
gives
w =
4×16 char array
'098F00D9C800EFCD'
'24B8006015001AB2'
'6670008988002E80'
'8B0000C600007500'
If you need literal spaces in between each byte, that can be done instead:
wo = reshape(k(1:2:end),4,[]);
we = reshape(k(2:2:end),4,[]);
ws = repmat(' ',[4 8]);
w = reshape([wo; we; ws],4,[])
gives
w =
4×24 char array
'09 8F 00 D9 C8 00 EF CD '
'24 B8 00 60 15 00 1A B2 '
'66 70 00 89 88 00 2E 80 '
'8B 00 00 C6 00 00 75 00 '
Note the method of stacking arrays to implement the striping behavior.

Plus de réponses (1)

Walter Roberson
Walter Roberson le 3 Mai 2021
Modifié(e) : Walter Roberson le 3 Mai 2021
compose("%02x", reshape(sscanf(k,'%2x'),4,[]))
This will return a 4 x 8 string array, not a char array. If you want a 4 x 8 array, then you need to use a cell array or a string array, or you need to convert to decimal. The reshape(sscanf(k,'%2x'),4,[]) part is doing the conversion to decimal and re-ordering of values.

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