Need to solve the code?
2 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
POTTA SATEESH
le 3 Mai 2021
Commenté : POTTA SATEESH
le 4 Mai 2021
u1 = 0.32;
v1 = 0.032;
u2 = 1400000;
v2 = 70000;
u3 = 100;
v3 = 40;
a1 = -0.5;
a2 = -0.5;
a3 = 0.707;
A1 =0;
A2 = 0;
A3 = 0;
U3 = 0;
V3 = 0;
S = 1;
K = 0;
B1 = 5;
delta = 0.001;
LM = (u3^2)/(sqrt((u3^2)+(v3^2)));
LS = sqrt(log(1+((v3^2)/(u3^2))));
X1 = @(z1,u1,v1) (u1+(v1*z1));
X2 = @(z2,u2,v2) (u2+(v2*z2));
X3 = @(z3,U,V) (U+(V*z3));
f = @(X1,X2,X3,z1,u1,v1,z2,u2,v2,z3,U,V) ((X1(z1,u1,v1)*X2(z2,u2,v2))-(2000*X3(z3,U,V)));
while (abs(A1-a1)>0.01 && abs(A2-a2)>0.01 && abs(A3-a3)>0.01 && abs(U3-u3)>0.01 && abs(V3-v3)>0.01)
if S~=1
a1 = A1;
a2 = A2;
a3 = A3;
u3 = U3;
v3 = V3;
end
U = u3;
V = v3;
% B1 = (-((44800*a1)+(22400*a2)-(2000*V*a3))+sqrt(((44800*a1)+(22400*a2)-(2000*V*a3))^2-(4*(2240*a1*a2)*(-2000*U))))/(2*2240*a1*a2);
% B2 = (-((44800*a1)+(22400*a2)-(2000*v*a3))-sqrt(((44800*a1)+(22400*a2)-(2000*v*a3))^2-(4*(2240*a1*a2)*(-2000*u))))/(2*2240*a1*a2);
z1 = a1*B1;
z2 = a2*B1;
z3 = a3*B1;
A1 = (f(X1,X2,X3,z1+delta,u1,v1,z2,u2,v2,z3,U,V)-f(X1,X2,X3,z1,u1,v1,z2,u2,v2,z3,U,V))/(delta);
A2 = (f(X1,X2,X3,z1,u1,v1,z2+delta,u2,v2,z3,U,V)-f(X1,X2,X3,z1,u1,v1,z2,u2,v2,z3,U,V))/(delta);
A3 = (f(X1,X2,X3,z1,u1,v1,z2,u2,v2,z3+delta,U,V)-f(X1,X2,X3,z1,u1,v1,z2,u2,v2,z3,U,V))/(delta);
K = (sqrt((A1)^2+(A2)^2+(A3)^2));
A1 = -(A1)/K;
A2 = -(A2)/K;
A3 = -(A3)/K;
X3 = U+(A3*B1*V);
V3 = (X3*LS);
U3 = X3*(1-log(X3)+log(LM));
S = S+1;
end
error:
Index in position 1 is invalid. Array indices must be positive integers or logical values.
Error in newtrail_1>@(X1,X2,X3,z1,u1,v1,z2,u2,v2,z3,U,V)((X1(z1,u1,v1)*X2(z2,u2,v2))-(2000*X3(z3,U,V))) (line 24)
f = @(X1,X2,X3,z1,u1,v1,z2,u2,v2,z3,U,V) ((X1(z1,u1,v1)*X2(z2,u2,v2))-(2000*X3(z3,U,V)));
Error in newtrail_1 (line 40)
A1 = (f(X1,X2,X3,z1+delta,u1,v1,z2,u2,v2,z3,U,V)-f(X1,X2,X3,z1,u1,v1,z2,u2,v2,z3,U,V))/(delta);
0 commentaires
Réponse acceptée
Walter Roberson
le 3 Mai 2021
X3 = @(z3,U,V) (U+(V*z3));
So X3 is a function handle.
X3 = U+(A3*B1*V);
So X3 is a numeric variable now.
But you are inside a loop, and when you go back, X3 is still a numeric value but will be expected to be a function handle.
3 commentaires
Walter Roberson
le 4 Mai 2021
u1 = 0.32;
v1 = 0.032;
u2 = 1400000;
v2 = 70000;
u3 = 100;
v3 = 40;
a1 = -0.5;
a2 = -0.5;
a3 = 0.707;
A1 =0;
A2 = 0;
A3 = 0;
U3 = 0;
V3 = 0;
S = 1;
K = 0;
B1 = 5;
delta = 0.001;
LM = (u3^2)/(sqrt((u3^2)+(v3^2)));
LS = sqrt(log(1+((v3^2)/(u3^2))));
X1 = @(z1,u1,v1) (u1+(v1*z1));
X2 = @(z2,u2,v2) (u2+(v2*z2));
X3 = @(z3,U,V) (U+(V*z3));
f = @(X1,X2,X3,z1,u1,v1,z2,u2,v2,z3,U,V) ((X1(z1,u1,v1)*X2(z2,u2,v2))-(2000*X3(z3,U,V)));
while (abs(A1-a1)>0.01 && abs(A2-a2)>0.01 && abs(A3-a3)>0.01 && abs(U3-u3)>0.01 && abs(V3-v3)>0.01)
if S~=1
a1 = A1;
a2 = A2;
a3 = A3;
u3 = U3;
v3 = V3;
end
U = u3;
V = v3;
% B1 = (-((44800*a1)+(22400*a2)-(2000*V*a3))+sqrt(((44800*a1)+(22400*a2)-(2000*V*a3))^2-(4*(2240*a1*a2)*(-2000*U))))/(2*2240*a1*a2);
% B2 = (-((44800*a1)+(22400*a2)-(2000*v*a3))-sqrt(((44800*a1)+(22400*a2)-(2000*v*a3))^2-(4*(2240*a1*a2)*(-2000*u))))/(2*2240*a1*a2);
z1 = a1*B1;
z2 = a2*B1;
z3 = a3*B1;
A1 = (f(X1,X2,X3,z1+delta,u1,v1,z2,u2,v2,z3,U,V)-f(X1,X2,X3,z1,u1,v1,z2,u2,v2,z3,U,V))/(delta);
A2 = (f(X1,X2,X3,z1,u1,v1,z2+delta,u2,v2,z3,U,V)-f(X1,X2,X3,z1,u1,v1,z2,u2,v2,z3,U,V))/(delta);
A3 = (f(X1,X2,X3,z1,u1,v1,z2,u2,v2,z3+delta,U,V)-f(X1,X2,X3,z1,u1,v1,z2,u2,v2,z3,U,V))/(delta);
K = (sqrt((A1)^2+(A2)^2+(A3)^2));
A1 = -(A1)/K;
A2 = -(A2)/K;
A3 = -(A3)/K;
X3_var = U+(A3*B1*V);
V3 = (X3_var*LS);
U3 = X3_var*(1-log(X3_var)+log(LM));
S = S+1;
end
However, if you need X3 to be a function that is changing in time, then you would need different code.
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Install Products dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!