how to do conditional statements using optimisation variables?

16 vues (au cours des 30 derniers jours)
NN
NN le 4 Mai 2021
Commenté : Julian le 21 Juil 2023
hi all, how can i perform logical comparison using optimisation variable ?
I have tried this below code for optimisation using optimisation variable PbattV , but getting error :
Cost = Costa.*(PbattV<=200) +Costb.*(PbattV>=200);
P1= dt*Cost'*PbattV;
P2=dt*Cost'*PbattV;
P=P1-P2;
prob.ObjectiveSense = 'minimize';
prob.Objective = P;
An error occurred while running the simulation and the simulation was terminated Caused by: times Please help if you have any suggestion
basically i need to check if Pbatt is positive or negative and accordingly i have to chose Cost and use it for objective function;
  1 commentaire
Julian
Julian le 21 Juil 2023
Hi NN, I wanted to ask If you have found a working solution for your problem?
Have you found a way to rewrite your Problem?

Connectez-vous pour commenter.

Réponse acceptée

Walter Roberson
Walter Roberson le 4 Mai 2021
Cost = Costa.*(PbattV<=200) +Costb.*(PbattV>=200);
Optimization variables cannot be converted to logical values. The only time you can compare an optimization variable to a value is in constructing a constraint.
Give up on trying to code it in terms of comparison operators: you will not succeed.
If there is a solution, then it will involve using mathematical tricks such as sqrt(x^2)/x to get the sign(x)
  17 commentaires
NN
NN le 19 Août 2021
Ok.Still when it doesnt support another function with conditional statements, or even constraints, i cant perform that operation.
I am thinking some other approach without considering sign change
Walter Roberson
Walter Roberson le 21 Août 2021
When you have discontinuous derivatives, the alternative supported by MATLAB are:

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Surrogate Optimization dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by