A simple for loop question

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Ulrich Achas
Ulrich Achas le 9 Mai 2021
Commenté : Ulrich Achas le 9 Mai 2021
isb=6;
for i=1:3
nta=(1+isb).^2/isb
isb=nta;
end
Hello everyone. I have just started to use MATLAB and I wrote the code above. My question is: When I ran this code, MATLAB gave me only last value of nta. But I need all nta values as an matrix. How can I write it? Thanks.
  2 commentaires
Jonas
Jonas le 9 Mai 2021
use nta(i) in both cases
Ulrich Achas
Ulrich Achas le 9 Mai 2021
thank you.

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Mazdack Ameri
Mazdack Ameri le 9 Mai 2021
Modifié(e) : Mazdack Ameri le 9 Mai 2021
you could do something like this:
isb=6;
nta_matrix = zeros(3,1); %initializing, it usually saves memory.
for i=1:3
nta_matrix(i) = (1+isb).^2/isb;
isb=nta_matrix(i);
end
  1 commentaire
Ulrich Achas
Ulrich Achas le 9 Mai 2021
it worked, thank you so much.

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