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How to assign a row matrix to another row matrix

2 vues (au cours des 30 derniers jours)
Andrea Sbaragli
Andrea Sbaragli le 11 Mai 2021
Commenté : Andrea Sbaragli le 11 Mai 2021
This is my function:
function [T1,T2, T3] = dispatch(A)
T1 = zeros(size(A));
T2 = zeros(size(A));
T3 = zeros(size(A));
i=1;
j=1;
k=1;
z=1;
for i=1:height(A)
s=1;
if A {i,2}== 1; % tagID=1
for s=1:4
T1 (j,s) = (A(i,s));
s=s+1
end
j= j+1;
end
if A{i,2}== 2; % tagID=2
for s=1:4
T2(k,s) = A(i,s);
s=s+1
end
k= k+1;
end
if A{i,2}== 3; % tagID=3
for s=1:4
T3(z,s) = (A(i,s));
s=s+1
end
z= z+1;
end
i = i+1;
end
end
it returns me that error:
The following error occurred converting from table to double:
Undefined function 'double' for input arguments of type 'table'. To convert to numeric, use the TABLE2ARRAY function, or extract data using dot or brace subscripting.

Réponses (1)

Jan
Jan le 11 Mai 2021
Modifié(e) : Jan le 11 Mai 2021
The error message suggests:
To convert to numeric, use the TABLE2ARRAY function
Did you try this already?
In one line you write:
if A {i,2}== 1
So you decided to use the brace indexing. Then you write:
T1 (j,s) = (A(i,s))
Now you try to use the parentheses. Why?
  1 commentaire
Andrea Sbaragli
Andrea Sbaragli le 11 Mai 2021
if A {i,2}== 1 here I used these brackets because == was not supported otherwise
T1 (j,s) = (A(i,s)) here brace index returns me the same error.
Yes I have already use table2array function but it does not work.
It is strange because inside A all values are in double format..

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