modify a row of an array within a function
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I have a 2 dimensional array arr and at various places i want to replace the ii-th row.
So I would like to write a function
function arr = replace(arr, ii)
and call that, e.g. in a loop but also with fixed ii.
My problem is that i fear that all of arr is copied then.
I just want a passed by reference and replace the row.
Is this feasable??
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Stephen23
le 18 Mai 2021
"My problem is that i fear that all of arr is copied then."
Have you checked this?
Réponses (2)
KSSV
le 18 Mai 2021
If a is an array of size m*n, you can repalce i'th row with a row matrix b of size 1*n using:
a(i,:) = b ;
James Tursa
le 18 Mai 2021
Modifié(e) : James Tursa
le 18 Mai 2021
This can sometimes be done inplace depending on how you write the function and how you call the function. One requirement is your function needs to be called from within another function (easy to do). Another requirement is that your variable can't be shared with another variable (not easy to guarantee unfortunately). See this blog:
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