count groups of elements and distances between them

Dear, Colleagues:

Let's say I have a matrix:

A= [6 6 6 4 4 4 4 4 6 5 5 7 7 7 8 9 8 7 0 0 0 0]

I would like to count number of six and number of zeros (as a group of consequent elements).

And, I would also like to know the distance between groups.

The Matlab output that I would like to get: _____________________________________________________________________________

There are two groups of 6 and one group of 0s.

L= [3 1 4] - length of each group

D= [5 9] - distance between groups

Thank you in advance.

Answer 1

[Andrei Bobrov]

A= [6 6 6 4 4 4 4 4 6 5 5 7 7 7 8 9 8 7 0 0 0 0];
a = A == 6 | A == 0;
a1 = [0 a(:)' 0];
i1 = strfind(a1,[0 1]);
i2 = strfind(a1,[1 0]);
L = i2 - i1;
D = i1(2:end) - i2(1:end-1);

or

A= [6 6 6 4 4 4 4 4 6 5 5 7 7 7 8 9 8 7 0 0 0 0];
a = [A(:) == 6 | A(:) == 0 ; false];

b = [true;diff(a(:))~=0];
bn = find(b);
idx = bn(cumsum(a(b))>0);
LD = diff(idx);
L = LD(1:2:end);
D = LD(2:2:end);

Answer 2

[Richard Brown]

A = [6 6 6 4 4 4 4 4 6 5 5 7 7 7 8 9 8 7 0 0 0 0];
x = diff([find(diff([0 ismember(A, [0 6]) 0]))]);
L = x(1:2:end);
D = x(2:2:end);

[Azzi Abdelmalek]

What if

A= [5 6 6 6 4 4 4 4 4 6 5 5 7 7 7 8 9 8 7 0 0 0 0 0 1];

[Richard Brown]

Still works fine ...

[Azzi Abdelmalek]

>> L
L =
   1     5     9
>> D
D =
   3     1     4

L should be [3 1 5]

[Richard Brown]

I think you've typed it in wrong ... if I run it on your A I get L = [3 1 5], D = [5 9]

[Azzi Abdelmalek]

I copied your, code, maybe before you edited it.

[Richard Brown]

Ah, I thought I'd corrected it fast enough that noone would notice. Sorry about that.

[Azzi Abdelmalek]

I 've made some speed test, Richards code is the fastest

Answer 3

[Azzi Abdelmalek]

A= [6 6 6 4 4 4 4 4 6 5 5 7 7 7 8 9 8 7 0 0 0 0];
A=num2str(A);
A(A==' ')='';
[a0,a1,group0]=regexp(A,'[06]+','start','end','match');
longueur=a1-a0+1  % length of groups
id=diff(sort([a0 a1 ]))-1  ;
id=id(2:2:end)% distance between groups
group0 % your groups

%or with Richard's idea

idx=1:numel(A)+2;
A=A~=0 & A~=6 ;
id=diff(idx(~~(diff([0 ~A 0]))));
L1=id(1:2:end);
D1=id(2:2:end);

Answer 4

[VT]

Colleagues. Thank you for the fast response. Especially, I like the simplicity of codes without a need to create loops.