Interpolating between two 3d time dependent positions

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River Vorse
River Vorse le 1 Juin 2021
I'm trying to interpolate between 3d position values seperated by a 1 minute timestep. I have an array of position data <x,y,z> of size [500,000 x 3]. Each row of 3 values <x,y,z> represents a point in 3d space at a specific time (ex. 2 minutes). I'm trying to interpolate between each value so that I have a timestep in my data of 1 second. So I want to generate 59 pts between minute 1 and minute 2. For example: If t1 = 1min, <x1,y1,z1> = <1,1,1> and t2 = 2min, <x2,y2,z2> = <2,2,2>, then t3 = 1min 30 seconds and <x3,y3,z3> might equal ~ <1.5,1.5,1.5> using a linear interpolation method. My inclination is to use interpn(). Could anyone direct me how to set this up?
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Tahariet Sharon
Tahariet Sharon le 8 Mar 2023
I have the same problem, only that instead of 3 points in space I have a whole 3D matrix in space at a given point.
I have 10 points in time for different configuations of the 3D matrix, and I want to interpolate several time points between each data point. How to go about this?

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Adam Danz
Adam Danz le 1 Juin 2021
Modifié(e) : Adam Danz le 1 Juin 2021
There are multiple ways to do this. Here I show how to put your (x,y,z) coordinates into a timeseries and use resample to interpolate the 3D coordinates.
Main functions
Create an mx3 matrix of [x,y,z] coordinates
xyz is the only input in this demo. The rest of the demo can be copy-pasted.
th = linspace(0,31.5,50)';
xyz = [sin(th),cos(th),th];
Create a timeseries object at 2-minute intervals and interpolate at 60-sec intervals
Create an mx1 vector of time stamps at 2-minute intervals
timestamps = (0:2:size(xyz,1)*2-1)'; % minutes; col vector!x
Create a timeseries object
ts = timeseries(xyz, timestamps, 'Name', 'XYZdata'); % name optional
ts.TimeInfo.Units = 'Minutes';
Create an nx1 vector of time stamps at 1-second resolution. The vector spans the range of timestamps in your raw-data.
timestampsInterp = ts.Time(1) : 1/60 : ts.Time(end);
Interpolate, or resample at the new timestamps created above. Interpolation is linear by default; see the timeseries interpolation method in ts.DataInfo.Interpolation. See other interpolation options in resample>interpmethod and timeseries>DataInfo.
tsInt = resample(ts,timestampsInterp);
Extract the interpolated xyz data to an nx3 matrix (xyzInt). Note that this step could be skipped and you could work with the interpolated timeseries object directly.
xyzInt = tsInt.Data;
Plot the original and interpolated data
If you're planning on plotting your data, you may want to plot a subsection of the data since it is much larger than these demo data and will take a long time to render and will comsume much memory.
figure()
plot3(xyz(:,1),xyz(:,2),xyz(:,3),'bo','LineWidth',2,'DisplayName','Original (2-min)')
hold on
plot3(xyzInt(:,1),xyzInt(:,2),xyzInt(:,3),'r.','MarkerSize',3,'DisplayName','Interpolated (1-sec)')
grid on
legend('Location','SouthOutside')
Store the new interpolated data in a timetable
This, of course, is optional but it will be useful if you're planning on doing further time-based analysis.
TT = array2timetable(tsInt.Data,...
'RowTimes',seconds(tsInt.Time*60), ...
'VariableNames', {'x','y','z'});
head(TT) % view the first few rows
ans = 8×3 timetable
Time x y z _____ _________ _______ _________ 0 sec 0 1 0 1 sec 0.0049957 0.99834 0.0053571 2 sec 0.0099914 0.99667 0.010714 3 sec 0.014987 0.99501 0.016071 4 sec 0.019983 0.99335 0.021429 5 sec 0.024979 0.99168 0.026786 6 sec 0.029974 0.99002 0.032143 7 sec 0.03497 0.98836 0.0375
  2 commentaires
Adam Danz
Adam Danz le 2 Juin 2021
Another approach may be to convert the data to a timetable at 2 min intervals and use retime to interpolate to seconds.
Tahariet Sharon
Tahariet Sharon le 8 Mar 2023
I have the same problem, only that instead of 3 points in space I have a whole 3D matrix in space at a given point.
I have 10 points in time for different configuations of the 3D matrix, and I want to interpolate several time points between each data point. How to go about this?

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