How to quickly find out the repeat integers in an array?

3 vues (au cours des 30 derniers jours)
Benson Gou
Benson Gou le 3 Juin 2021
Commenté : Benson Gou le 4 Juin 2021
Dear All,
I have an array A which contains repeat intergers (entries). For example, A = [4 20 5 4 7 5 9 5 31]. I want to find out the repeat elements {4, 5} and their locations.
Thanks.
Benson

Réponse acceptée

Akira Agata
Akira Agata le 3 Juin 2021
I believe it's time to use accumarray function!
How about the following?
A = [4 20 5 4 7 5 9 5 31];
B = accumarray(A',1);
pt = find(B >= 2);
loc = arrayfun(@(x) find(x == A),pt,'UniformOutput',false);
tResult = table(pt,loc,'VariableNames',{'Value','Location'});
The result is like this:
>> tResult
tResult =
2×2 table
Value Location
_____ _________
4 {[ 1 4]}
5 {[3 6 8]}
  1 commentaire
Walter Roberson
Walter Roberson le 3 Juin 2021
At the time I was composing my own reply, I didn't think anyone else would give an accumarray solution ;-)
There are a few differences between the above and my first solution:
  • my version supports negative integers
  • I "compress" the range of values in a sense: if the mininum integer happens to be large, a straight accumarray could waste a lot of space, whereas my version does not use up any space between 0 and the lowest integer
  • but both versions potentially waste a lot of space: if for example A was [1 1e6+1 2e6+1] then both of them waste a lot of memory
  • we handle the matches differently. Akira's version searches through the data once plus one time for every unique value; my version searches through the data once

Connectez-vous pour commenter.

Plus de réponses (1)

Walter Roberson
Walter Roberson le 3 Juin 2021
A = [4 20 5 4 7 5 9 5 31]
A = 1×9
4 20 5 4 7 5 9 5 31
mA = min(A(:)) - 1;
At = A(:) - mA;
locs = accumarray(At, (1:length(At)), [], @(V) {V.'});
dups = cellfun(@length,locs) > 1;
info = [num2cell(At(dups)+mA), locs(dups)]
info = 2×2 cell array
{[ 4]} {[ 1 4]} {[20]} {[3 6 8]}
... but most people might find that too obscure. Less obscure might be
[G, uA] = findgroups(A);
info = cell(0,2);
for K = 1 : max(G)
matches = find(G == K);
if length(matches) > 1
info(end+1,:) = {uA(K), matches};
end
end
info
info = 2×2 cell array
{[4]} {[ 1 4]} {[5]} {[3 6 8]}
  1 commentaire
Benson Gou
Benson Gou le 4 Juin 2021
Hello, Walter,
Thanks a lot for your great help. You have a good weekend!
Benson

Connectez-vous pour commenter.

Catégories

En savoir plus sur Call Python from MATLAB dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by