Hi,
I am doing some operation with for loop. The result of each iteration, let's say F1 needs to be svaed in the big matrix G as shown below.
for i = 1:1:10
G (:,:,i) = F1
end
However, the size of the matrix F1 varies for each iteration, owing to this I am getting the following error, Any idea how to handle this
Unable to perform assignment because the size of the left side is 1-by-1444 and the size of the right side is 1-by-1225.

 Réponse acceptée

KSSV
KSSV le 3 Juin 2021
Modifié(e) : KSSV le 3 Juin 2021

0 votes

When the size of matrix varies, the option to save the matrix is a cell array.
G = cell(10,1) ;
for i = 1:1:10
G{i} = F1 ;
end
Later you can access the matrices using cell indexing. G{1}, G{2},....G{10}

3 commentaires

Big Data
Big Data le 3 Juin 2021
Thanks a lot.. !!!!!!!!!!
Now, I can save the data
KSSV
KSSV le 3 Juin 2021
Thanks is accepting/ voting the answer. :)
Big Data
Big Data le 3 Juin 2021
Sorry.. Forgot to do.. Done now..
Cheers !!!!

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