While loop and randomization
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Thank you in advance for your help!
if (valCount == ones)
disp(y1)
else
disp('repetition')
end
% this if/end works manually, but it's not a while loop, so it doesn't work
% automatically...
1 commentaire
Jan
le 7 Juin 2021
Unfortuantely you have removed important parts of your question. Please don't do this. The nature of this forum is sharing problems and solution. The voluntary users spend time to help you and they want the thread to be useful for others also.
Réponses (1)
Jan
le 6 Juin 2021
Modifié(e) : Jan
le 6 Juin 2021
x = [1 1 1 2 2 2 3 3 3];
ready = false;
while ~ready
y1 = [x(randperm(numel(x))); x(randperm(numel(x))); x(randperm(numel(x)))];
ready = numel(unique(y1(:, 1))) == size(y1, 1);
end
Instead of a rejection you can use an constructive method:
x = [1 1 1 2 2 2 3 3 3];
nx = numel(x);
ux = unique(x);
nRow = 3;
y1 = zeros(nRow, nx);
for k = 1:nRow
v = x(randperm(nx));
v(find(v == ux(k), 1)) = [];
y1(k, :) = [ux(k), v];
end
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