Include value requirement in array multiplication
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I currently have the following line of code:
dS=k1*cA(i+1,:).*cB(i+1,:)*dt
dS is the amount of product S resulting from a reaction between A and B, which reaction has a rate constant of k1. cA and cB are the concentrations of A and B respectively and dt is the time step.
Now I would like to specify that a dS value should only be calculated if both the cA cell value and cB cell value which are being multipled are greater than a specific value - in this case 1E-04. If either cA or cB is less than this value, then the result of the multiplication should be zero.
How would I program this requirement in MatLab?
0 commentaires
Réponses (2)
Sulaymon Eshkabilov
le 19 Juin 2021
for ii=1:N
if cA>1e-4 & cB>1e-4
dS=k1*cA(i+1,:).*cB(i+1,:)*dt;
else
dS = 0;
end
end
1 commentaire
Sulaymon Eshkabilov
le 19 Juin 2021
Modifié(e) : Sulaymon Eshkabilov
le 19 Juin 2021
...
N = size(cA, 1);
for ii=1:N
if cA>1e-4 & cB>1e-4
dS(ii,:)=k1*cA(ii,:).*cB(ii,:)*dt;
else
dS(ii,:) = 0;
end
end
%%
Alternative and most efficient way is vectorization and logical indexing:
dS=k1*cA.*cB*dt;
IDX = (cA<1e-4 & cB<1e-4); % Logical indexing
dS(IDX,:)=0; % Takes care of both conditions cA<1e-4 & cB<1e-4
2 commentaires
Sulaymon Eshkabilov
le 19 Juin 2021
Consider the vectorization approach that is much more efficient and fast.
Voir également
Catégories
En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!