How to define both integer and decimal increment in one for loop?
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Hi all,
I would like to define one for loop that goes from 0 to 1 with an increment of 0.1 and then goes from 1 to 30 by an increment of 2, i.e., combination of the following two loops. Is it possible? If so, how?
for n = 1:2:30
f(round((n-1)/2+1)) = ....
end
z = 0: 0.1: 1;
for n = 1: length(z)
f(n) = ..
end
Thanks in advance
0 commentaires
Réponse acceptée
Image Analyst
le 23 Juin 2021
Try this:
allValues = [0:0.1:1, 3:2:30];
numValues = length(allValues)
% Preallocate some results we want to store in the loop.
results = zeros(1, numValues);
% Now loop over all values.
for k = 1 : numValues
thisValue = allValues(k);
fprintf('Processing element #%d of %d, which is %f.\n', ...
k, numValues, thisValue);
% results(k) = YourFunction(thisValue);
end
Plus de réponses (1)
millercommamatt
le 23 Juin 2021
I'm not clear on what you're looking for. Do you want something like this:
span1 = 0:0.1:1;
span2 = 3:2:30;
span = [span1 span2];
for ii = span
% do something with ii...
end
7 commentaires
Steven Lord
le 24 Juin 2021
@Matthew I suspect Image Analyst was replying to Susan's message not yours. The comment "do something with ii..." suggests to me (and I suspect to Image Analyst as well) that Susan wanted output(ii).
Image Analyst
le 24 Juin 2021
I was responding to Susan and just said No, then I went to MATLAB to develop code that works. Then I came back here to further explain why it wouldn't work and edited my comment but then I didn't notice miller's comment since it was posted while I was working on the code in MATLAB, and I mistakenly copied the loop from miller's comment instead of Susan's (not noticing that millers was a new comment). Sorry for the misunderstanding, that sometimes happens when people are posting at the same time. miller's code snippet #2 will also work for Susan.
Voir également
Catégories
En savoir plus sur Feature Detection and Extraction dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!