How to build ratio between two columns of a matrix?

I have a matrix of size 102 x 2555 I want to select each column from 1 to 2555 of this matrix and then divide to each column of this matrix. For example: I have matrix

A=

   1 2 3 4 5 6
   2 3 4 5 6 7
   3 4 5 6 4 6
   5 6 8 7 1 3

I want to build the ratios like this:

ratio1=column1./each column in matrix A

ratio2=column2./each column in matrix A

ratio3=column3./each column in matrix A

....

ratio6=column6./each column in matrix A

Thanks for your help!

Answer 1

[the cyclist]

A= ...
   [1 2 3 4 5 6; ...
   2 3 4 5 6 7; ...
   3 4 5 6 4 6; ...
   5 6 8 7 1 3];

[nrow,ncol] = size(A);

for n = 1:ncol

      ratio{n} = bsxfun(@rdivide,A(:,n),A)

end

[Viet Duc]

Thanks for your help!

But it's out of memory

Size of my matrix is 2555 columns and 102 rows :(

[the cyclist]

Hm. I can run this code with no problem.

A = rand(102,2555);
[nrow,ncol] = size(A);

ratio = cell(2555,1);

for n = 1:ncol
    ratio{n} = bsxfun(@rdivide,A(:,n),A);    
end

[Jan]

@Viet Duc: As result you get 2555 matrices of type double with 102*2555 elements, which occupy about 5.32 GB. With a 16 GB machine and a 64 bit system, this is no problem, but it fails for a 32 bit machine.

Do you really need such a large pile of data simultaneously in the memory?

[Andrei Bobrov]

num2cell(bsxfun(@rdivide,permute(A,[1 3 2]),A),[1 2])

Answer 2

[Viet Duc]

Thank you all.

Maybe, I should check my matrix and remove some columns and rows