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how to assign zero value to all pixels in an image ?

14 vues (au cours des 30 derniers jours)
sheno39
sheno39 le 11 Sep 2013
assign zero value to pixel

Réponse acceptée

Jan
Jan le 11 Sep 2013
It depends on what an "image" is. Please post more details in future questions. Fortunately the procedure to set the values to 1 is equal:
Img = rand(1024, 768, 3); % RGB image
Img(:) = 0;
Img2 = randi([0, 255], 1024, 768, 'uint8');
Img2(:) = 0;
  2 commentaires
sheno39
sheno39 le 11 Sep 2013
thanks a lot. as am beginner in matlab programming, i do not how to do the code.. i need the code for following function: function computedensity() for x in all pixels p[x] = 0; for n in all pixels less than 3 p[x]+=exp(-(f[x]-f[n])^2
Jan
Jan le 12 Sep 2013
Modifié(e) : Jan le 12 Sep 2013
This is a completely new question. Please ask it in a new thread.
"for n in all pixels less than 3 " is not clear to me. What is "f"?

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Plus de réponses (2)

sidra
sidra le 11 Sep 2013
I don't understand what purpose setting all the pixel values to zero would achieve.
Nevertheless One of the method is:
You can use two for loops starting from 1 to you image size and the within these loops set the pixel values to zero. Something of this sort
for i=1:n
for j=1:m
img(i,j)=0;
end
end
where n and m are the number of rows and columns respectively.
  2 commentaires
sheno39
sheno39 le 11 Sep 2013
thanks for your answer.. how to code the following.. kindly reply.. function computedensity() for x in all pixels p[x] = 0; for n in all pixels less than 3 p[x]+=exp(-(f[x]-f[n])^2
Image Analyst
Image Analyst le 11 Sep 2013
% Find all pixels < 3
binaryImage = f < 3; % binaryImage is what you called x
Now, what's f(n)? What is n? In f(x), x is all pixels less than 3. But what is n in f(n)?

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Image Analyst
Image Analyst le 11 Sep 2013
Yet another way
grayImage = zeros(size(grayImage), 'uint8');
  1 commentaire
sheno39
sheno39 le 11 Sep 2013
Modifié(e) : sheno39 le 11 Sep 2013
thanks for your help.. can u help me to code the following.. kindly reply.. function computedensity() for x in all pixels p[x] = 0; for n in all pixels less than 3 p[x]+=exp(-(f[x]-f[n])^2

Connectez-vous pour commenter.

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