using normrnd function in a loop

If I use normrnd function in a loop, every times that normrnd runs in a new loop it will give me the same number? ( if I set parameters to a constant value);

for i = 1 :10
x(i) = normrnd(1,0.2);
end

Answer 1

[the cyclist]

No. It will give a different number on every call (until you reach the end of the pseudorandom generator's period, which is enormous).

Answer 2

[Azzi Abdelmalek]

rng(14) % choose your seed
for i = 1 :10
x(i) = normrnd(1,0.2)
end