Convolution of rect (t/2) and δ(t+2) - δ(t+1)

how can i plot this: g(t) = rect(t/2) * [δ(t+2) - δ(t+1)]. As matter of fact, i want to plot the convolution of this functions. But i'm having trouble creating the rect function. If anyone can help me, i would appreciate it very much.

 Réponse acceptée

Image Analyst
Image Analyst le 14 Sep 2013
You can make a rect function by making an array of zeros and placing stretch of 1's in it:
rectPulse = zeros(1, 20);
rectPulse(10:15) = 1;
plot(rectPulse, 'bs-');

Plus de réponses (1)

Azzi Abdelmalek
Azzi Abdelmalek le 13 Sep 2013
Modifié(e) : Azzi Abdelmalek le 13 Sep 2013
rect=@(t) heaviside(t+1)- heaviside(t-1)

4 commentaires

daltonicox
daltonicox le 13 Sep 2013
tnx
Image Analyst
Image Analyst le 13 Sep 2013
Please mark "Accept" if that answered your question.
daltonicox
daltonicox le 13 Sep 2013
it didn't work, i'm missing something.
Azzi Abdelmalek
Azzi Abdelmalek le 13 Sep 2013
Ok, what are you missing?

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