Reading data into a structure

Hi, im reading the file:

26/09/2013,16:04:40 2412 928.0 49.94930
25/09/2013,14:24:30 2412 914.0 -999999

using:

fid = fopen('/path/to/your/file.txt', 'rt');
output = textscan(fid, '%s %s %f %f %f', 'Delimiter', ' ,');
fclose(fid);

now i want to read this into an array of structures s. I have tried using the following:

s.date = output{1};
s.time = output{2};

etc

however this gives me size(s) = 1 (a single structure with arrays of dates and times as members) I would prefer to have an array of structures each with a single date and time. Is this possible?

Answer 1

[Walter Roberson]

[s{1>length(output{1})}.date] = [output{1}{:}];
[s{:}.time] = [output{2}{:}];

Answer 2

[Azzi Abdelmalek]

%That's what you have

y=1:10
s.date=y

%result

s = 
  date: [1 2 3 4 5 6 7 8 9 10]

%and you want

s=struct('date',num2cell(y))

%result

s = 

1x10 struct array with fields:

    date