system of differential equations
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Hello All,
I am wondering how to solve system of differential equations using simulink?
plz do help me how to make a simulink model.
regards,
Réponses (7)
Titus Edelhofer
le 6 Juin 2011
0 votes
Hi,
you could open the vdp model as a typical second order differential equation. The way to go stays the same when you have a system: put as many integrators per row of your system as you have orders of differentiation, and feed them with the variables that make up the differential equation.
Titus
Arnaud Miege
le 6 Juin 2011
0 votes
Write down the equations on paper and then implement them using the various blocks available in Simulink. A tip: it's generally better to start with the highest order derivative and integrate rather than the other way round and differentiates. Have a look at Modeling Best Practises in the Simulink documentation and also at the interactive tutorials on the MathWorks web site.
HTH,
Arnaud
Seba
le 14 Juil 2011
0 votes
2 commentaires
Arnaud Miege
le 14 Juil 2011
That system does not have a solution. If you differentiate the second equation once more, you have:
x'' = -x' - z''
z'' = -1 - x'' - x'
If you then substitute the expression for z'' in the second equation into the first, you get:
x'' = -x' + 1 + x'' + x'
in other words, 1 = 0.
I suggest you check these equations, they're probably wrong.
ikhlas
le 3 Nov 2023
how can I solve this system using Euler's method in matlab
u'=p
v'=q
p'=0
q'=0
such that u(0)=0 , v(0)=0, p(0)=0, q(0)=1?
Seba
le 15 Juil 2011
0 votes
1 commentaire
Arnaud Miege
le 15 Juil 2011
Yes, as long there is a solution, you can represent any system of ODEs in Simulink. Start working out the higher order derivatives and use integrator blocks to work your way up. Read the documentation, e.g.:
http://www.mathworks.com/help/releases/R2011a/toolbox/simulink/ug/bra6ae8.html
Seba
le 19 Juil 2011
0 votes
3 commentaires
Arnaud Miege
le 19 Juil 2011
It's the same as with real-valued signals, see the documentation:
http://www.mathworks.com/help/releases/R2011a/toolbox/simulink/ug/f15-99132.html#f15-82250
There are blocks to combine the real and imaginary parts into a complex number and conversely, to split a complex number into its real and imaginary parts.
Seba
le 21 Juil 2011
Arnaud Miege
le 21 Juil 2011
Like I said before (read my previous answers/comments), you can represent any system of ODEs in Simulink. Start working out the higher order derivatives and use integrator blocks to work your way up. Read the documentation, e.g.:
http://www.mathworks.com/help/releases/R2011a/toolbox/simulink/ug/bra6ae8.html.
Also work through the tutorials I suggested and look at Modelling Best Practises in the documentation.
Seba
le 21 Juil 2011
0 votes
3 commentaires
Arnaud Miege
le 21 Juil 2011
There are two problems with the first example. The first one is a fairly simple syntax error: the correct MATLAB syntax is 10+10*i, not 10+10i (notice the *).
The second one is more subtle: even with the correct syntax, you'll get an error because you have an algebraic loop with a complex signals, which is not allowed. You will need to break the algebraic loop in some way. For example, adding a unit delay block with a sample time of say 1e-3s (or whatever is appropriate for your application), allows the model to run.
Walter Roberson
le 21 Juil 2011
Hmmm?
>> 10+10i
ans =
10 + 10i
Arnaud Miege
le 22 Juil 2011
OK, fair enough.
Seba
le 25 Juil 2011
0 votes
7 commentaires
Arnaud Miege
le 25 Juil 2011
This is an algebraic equation. Typically when you have a system of differential & algebraic equations, you would eliminate the algebraic variables and reduce the number of equations to the differential equations only before implementing in Simulink.
Seba
le 25 Juil 2011
Seba
le 25 Juil 2011
Arnaud Miege
le 25 Juil 2011
I have just told you this is an algebraic equation and k is an algebraic variable. If you have k in another (differential) equation, substitute for k the solution of this equation and then solve the differential equation in Simulink rather than what you're trying to do.
Walter Roberson
le 25 Juil 2011
10 + 10*i + 5*k = k
implies that
10 + 10*i + 5*k - k = 0
which implies that
10 + 10*i + 4*k = 0
which implies that
4*k = -10 - 10*i
which implies that
k = (-10 - 10*i)/4
which is
k = -2.5 - 2.5*i
Any simple variation on this problem can be solved with a math block.
Seba
le 26 Juil 2011
Walter Roberson
le 26 Juil 2011
http://www.mathworks.com/help/toolbox/simulink/slref/mathfunction.html
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