How to plot using a loop on the same axis
2 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Tebogo Makobe
le 14 Août 2021
Commenté : Tebogo Makobe
le 14 Août 2021
Would like to plot without having to hard code every single line up to 20+ customers(20 x 1 structure). Had an attempt at a for loop, the error message states that the number of element on the right are not same as on the left
%Graphical representation
t = 0:0.1:310; % Time vector for plots (m)
[position1,speed1,Duration1] = calcFallForPerson(customer(1),4200,0.1,1500);
[position2,speed2,Duration2] = calcFallForPerson(customer(2),4200,0.1,1500);
[position3,speed3,Duration3] = calcFallForPerson(customer(3),4200,0.1,1500);
[position4,speed4,Duration4] = calcFallForPerson(customer(4),4200,0.1,1500);
figure(1)
plot(t,position1,t,position2,t,position3,t,position4)
title('Posiion')
xlabel('Time(s)')
ylabel('Postion(m)')
xlim([0 320])
ylim([0 4500])
figure(2)
plot(t,speed1,t,speed2,t,speed3,t,speed4)
title('Velocity')
xlabel('Time(s)')
ylabel('Velocity(m/s)')
xlim([0 320])
ylim([0.0 60.0])
xlim([0 320])
ylim([0.0 60.0])
0 commentaires
Réponse acceptée
Wan Ji
le 14 Août 2021
Is the time array t the same size as position1,speed1 for each loop with different customers? If so, then following loop will help you!
t = 0:0.1:310; % Time vector for plots (m)
number_of_customer = 20; % change as you want
[position,speed,Duration] = arrayfun(@(i)acalcFallForPerson(customer(i),4200,0.1,1500),...
1:1:number_of_customer, 'uniform', false);
figure(1)
arrayfun(@(i)plot(t,position{i}),1:1:number_of_customer);
title('Posiion')
xlabel('Time(s)')
ylabel('Postion(m)')
xlim([0 320])
ylim([0 4500])
figure(2)
arrayfun(@(i)plot(t,speed{i}),1:1:number_of_customer);
title('Velocity')
xlabel('Time(s)')
ylabel('Velocity(m/s)')
xlim([0 320])
ylim([0.0 60.0])
xlim([0 320])
ylim([0.0 60.0])
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Line Plots dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!