How can I compute numerical integration from a multivariate function ( f(t,C) ) where C'=[c_1,c_2,...,c_m] with respect to " t "
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I want to find the numerical integration from a multivariate function ( f(t,C) ) where C'=[c_1,c_2,...,c_m] with respect to " t ",
what command is the most accurate and efficient Matlab command for doing this?
for example this is my function:
f(t,c_1,c_2,c_3,c_4) =
(t^2 + 1)*((5040315906112595*t^(3/5)*(156*c_1 - 156*3^(1/2)*c_2 + 156*5^(1/2)*c_3 - 156*7^(1/2)*c_4 + 195*3^(1/2)*c_2*t - 585*5^(1/2)*c_3*t + 1170*7^(1/2)*c_4*t + 450*5^(1/2)*c_3*t^2 - 2250*7^(1/2)*c_4*t^2 + 1250*7^(1/2)*c_4*t^3))/702561541869797376 + 1)^2 + (sin(t)*(c_1 - (exp(t)*((5040315906112595*t^(3/5)*(156*c_1 - 156*3^(1/2)*c_2 + 156*5^(1/2)*c_3 - 156*7^(1/2)*c_4 + 195*3^(1/2)*c_2*t - 585*5^(1/2)*c_3*t + 1170*7^(1/2)*c_4*t + 450*5^(1/2)*c_3*t^2 - 2250*7^(1/2)*c_4*t^2 + 1250*7^(1/2)*c_4*t^3))/702561541869797376 + 1))/2 + 3^(1/2)*c_2*(2*t - 1) + 5^(1/2)*c_3*(6*t^2 - 6*t + 1) + 7^(1/2)*c_4*(20*t^3 - 30*t^2 + 12*t - 1))^2)/cos(t)^2
note that the command " int ( f,t,0,1 ) " didn't work and it's said: Warning Explicit integral could not be found.
I'll be very appreciate if you help me with this.
Best regards,
Siavash.
Réponses (1)
Hi - a few things:
- INT is a Symbolic Math Toolbox command, so it will try to do the integration symbolically. In this case, since the function is quite complicated, it's having a hard time doing so.
- Instead, you probably want to try INTEGRAL if you have a recent enough MATLAB version, or QUAD otherwise.
- To handle the extra parameters, check out this doc page: Parameterizing Functions
Hope this helps!
2 commentaires
Siavash Kardar Tehran
le 17 Oct 2013
Yannick
le 17 Oct 2013
Hi Siavash,
Could you show your code here, as well as how you execute it and what result/warning/error you get? Then I can help figure out with you why it isn't working as expected.
Yannick
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