Effacer les filtres
Effacer les filtres

How do I join a single string with multiple strings?

3 vues (au cours des 30 derniers jours)
Tom Wright
Tom Wright le 17 Oct 2013
Commenté : Tom Wright le 17 Oct 2013
Hi, I know I can do this with loops but there must be a nicer way.
basepath='/data/';
filebase='video_';
fileext='.avi';
files=['00a' '00b' '00c'];
I'd like the output to be the vector
['/data/video_00a.avi' '/data/video_00b.avi' '/data/video_00c.avi']
(although I'd also be happy with a vertical matrix.
Thanks Tom
  1 commentaire
Matt Kindig
Matt Kindig le 17 Oct 2013
Modifié(e) : Matt Kindig le 17 Oct 2013
Are you sure you don't want 'files' to be a cell array? Because the way you've defined files, it will just concatenate 00a, 00b, etc. as one string. Observe:
files=['00a' '00b' '00c']
% files = '00a00b00c'
This is probably less useful to you. Instead, define 'files' as:
files = {'00a', '00b', '00c'}

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Azzi Abdelmalek
Azzi Abdelmalek le 17 Oct 2013
Modifié(e) : Azzi Abdelmalek le 17 Oct 2013
basepath='/data/';
filebase='video_';
fileext='.avi';
files={'00a', '00b', '00c'}
cellfun(@(x) sprintf([basepath filebase '%s' fileext],x),files,'un',0)
Look at
doc cell

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Vivek Selvam
Vivek Selvam le 17 Oct 2013
Here you go, Tom.
basepath = '/data/';
filebase = 'video_';
fileext = '.avi';
files = ['00a'; '00b'; '00c'];
n = size(files,1);
horzcat(repmat(basepath,n,1), repmat(filebase,n,1), files, repmat(fileext,n,1))

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