function ans = arraygcd(a)
% a=[45 15 200 300];
Note that all solutions (which passed the limited test suite with small size) involving only pair-wise gcd calculations are indeed incorrect. Those solutions include the following ones: 1) min(gcd(a,min(a))); 2) min(gcd(a(1), a)); 3) min(min(bsxfun(@gcd,a,a.'))); To eliminate these incorrect solutions, please simply add a test case with a = [21 15 35].
does it touch ?
Back to basics 11 - Max Integer
Close MATLAB with keyboard
Free passes for everyone!
Compress strings (not springs)
Volume of this donut
Minimum possible M of the maximum side of a triangle of given area A.
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