'u' in the function below is of type char or string and 'v' is of type int or double.
function y = your_fcn_name( u, v)
y = u / v;
find y ?!!
@Marco : Please check your solution. More test suits will make is fail.
@ Richard Zapoor : Check your solution. More test suits will make it fail.
Clean the List of Names
Return the 'Size' of a String of Code
Usage of varargout
Permute diagonal and antidiagonal
Split a string into chunks of specified length
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