Problem 1240. Coin change combinations.

Created by Ken

Solve Later

{"relationships":[{"relationshipType":"http://schemas.mathworks.com/matlab/code/2013/relationships/document","targetMode":"","relationshipId":"rId1","target":"/matlab/document.xml"},{"relationshipType":"http://schemas.mathworks.com/matlab/code/2013/relationships/output","targetMode":"","relationshipId":"rId2","target":"/matlab/output.xml"}],"parts":[{"partUri":"/matlab/document.xml","relationship":[],"contentType":"application/vnd.mathworks.matlab.code.document+xml","content":"<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n<w:document xmlns:w=\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\"><w:body><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>Using only pennies (1), nickels (5), dimes (10), quarters (25), half dollars (50), and dollars (100), how many different combinations can be made from a given amount in cents.</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>Example 1:</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>&gt;&gt;change(17)</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>%Output will be the the number of combinations of coins to make 17 cents.</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>c =</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"code\"/></w:pPr><w:r><w:t><![CDATA[   6]]></w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>There are 6 combinations:</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>17 pennies</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>12 pennies and 1 nickel</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>7 pennies and 2 nickels</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>2 pennies and 3 nickels</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>7 pennies and 1 dime</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>2 pennies, 1 nickel, and 1 dime.</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>Example 2:</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>&gt;&gt;change(100)</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>c =</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"code\"/></w:pPr><w:r><w:t><![CDATA[    293]]></w:t></w:r></w:p></w:body></w:document>"},{"partUri":"/matlab/output.xml","contentType":"text/xml","content":"<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"no\" ?><embeddedOutputs><metaData><evaluationState>manual</evaluationState><layoutState>code</layoutState><outputStatus>ready</outputStatus></metaData><outputArray type=\"array\"/><regionArray type=\"array\"/></embeddedOutputs>"}]}

Solve

Solution Stats

145 Solutions
45 Solvers

Last Solution submitted on Mar 07, 2022

Last 200 Solutions

Problem Comments

1 Comment

1 Comment

Alfonso Nieto-Castanon on 28 Feb 2013

please Ken, could you add a few more test cases of change(x) using x values greater than 100 to remove my (lame) look-up table leading solution? sorry!

Solution Comments

Solution 201475

2 Comments

2 Comments

Alfonso Nieto-Castanon on 7 Feb 2013

and while we are at it...

Khaled Hamed on 7 Feb 2013

well, ...

Solution 201443

1 Comment

1 Comment

Alfonso Nieto-Castanon on 7 Feb 2013

less 'redundant', more 'shorter' :)

Solution 201069

1 Comment

1 Comment

Khaled Hamed on 6 Feb 2013

Redundant, but shorter.

Solution 200747

1 Comment

1 Comment

Khaled Hamed on 6 Feb 2013

We are getting there... :)

Solution 199889

1 Comment

1 Comment

Alfonso Nieto-Castanon on 6 Feb 2013

nice, I did not know about combvec; those ever useful nnet functions :)

Problem Recent Solvers45

Problem Tags

math

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!