Find the mean of each consecutive pair of numbers in the input row vector. For example,
x=[1 2 3] ----> y = [1.5 2.5]
x=[100 0 0 0 100] ----> y = [50 0 0 50]
cheese
I added another test to the suite that invalidated this cheesy solution.
Why is eval forbidden while regexp isn't? Don't they have the same 'nature'?
It seems that the vast majority of leading solutions are size 10 or 11. If a problem has a single output, then having a return argument of 'ans' makes the size smaller. For instance:
function ans=findmean(x,y)
mean([x y])
is smaller in size than
function m=findmean(x,y)
m = mean([x y])
This seems silly, and makes me think that there is some 'trick' to these size 10&11 solutions that has little to do with good coding practices. Of course, it could just be sour grapes on my part because I can't get my sizes even close to that small.