Given the equation of a plan of the form ax+by+cz=d, return 2 independent direction vectors which could e.g. be used to determine a parametric equation.
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For the vectors to be independent, the test suite should have assert(dot(v1,v2)==0).
instead of assert(dot(v1,v2)~=0) ...
I agree. First, I did not succeed for that reason.
I am curious about the 26-node solution.
This is unfortunately suffering from many issues.
1. Many cases (planes parallel to one or two axes) aren't covered in the test suite.
2. Exact equality tests are used for floating-point comparisons, which can lead to spurious failures.
3. assert(dot(v1, v2) ~= 0) doesn't make sense, as remarked.
4. Neither would assert(dot(v1, v2) == 0), however, since the direction vectors are required to be (linearly) independent, not orthogonal.
Christian, I think the assertion dot(v1,v2)~=0 is placed to ensure that the two vectors are not parallel and therefore are independent.
I have modified the assert conditions and added some test cases to reflect planes parallel to axis/axes.
Thank you, Dyuman!
The test suite doesn't work for me?!
I think it should be -2d not only -d:
assert(abs(sum([a b c].*(v1+[0 0 d/c]))-2d)<1e-4)
And it could be way more readable:
assert(abs(a*v1(1) + b*v1(2) + c*v1(3) - d) < 1e-4)
How did some people solve this?!?
yup
nice