2^15 = 32768 and the sum of its digits is 3 + 2 + 7 + 6 + 8 = 26.
What is the sum of the digits of the number 2^N?
Thanks to Project Euler Problem 16.
added a test case to make it a wee bit harder
function y = pow2_sumofdigits(x)
number = sym(2^x);
n = char(number);
y = 0;
for i = 1:length(n)
y = y + str2double(n(i));
this code gives exact results on my mechine but not work in cody show error
Error: License checkout failed.
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Troubleshoot this issue by visiting:
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Licensing error: -5,0.
please help me ...........
It dseon't mettar waht oedrr the lrettes in a wrod are.
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