given the 1x5 vector x, y must be the square of the horizontal concatenation of the third and fifth elements. So, if x = [1 1 1 1 1], y must be [1 1].
The example you give in the problem statement is not very demonstrative.
HAHAHAHA Matt: this was great!!!
Replace NaNs with the number that appears to its left in the row.
Project Euler: Problem 6, Natural numbers, squares and sums.
Back to basics 15 - Benchmark
07 - Common functions and indexing 1
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