if a given matrix a = [1 2 3;4 5 6]; so answer is going to be [1 3;4 6]
Sans test cases with rank 11 (or even 3), it's too easy to provide a solution which passes the test but fails for, say, dyadics. Or did the originator really mean to stick with tensors (rank 2) of arbitrary x and y dimension?
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1164 Solvers
292 Solvers
123 Solvers
208 Solvers
Sum of odd numbers in a matrix
204 Solvers