Problem 44078. GJam 2017 Kickstart: Leader (Small)

Created by Richard Zapor

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This Challenge is derived from <a href = "http://code.google.com/codejam/contest/6304486/dashboard#s=p0">GJam 2017 Kickstart Leader</a>. This is the first 61 small cases with no spaces in names.<a href = "http://code.google.com/codejam">Google Code Jam 2017 Qualifier</a> is March 7, 2017. Typically four challenges with small and large aspects with 27 hours to complete.The GJam story is to determine the rightful leader. The leader is the person whose name utilizes the most unique letters, spaces do not count, and if two or more people are tied then the leader is the one whom comes first alphabetically, with space preceding A, given a list of 100 or fewer names.Input: [names], a cell array of names using only A thru Z; max 100 namesOutput: [Leader], a string of the name of the leaderExamples: [names] [Leader]; {'ADAM' 'BOB' JOHNSON'} ['JOHNSON']For the example the first two have three and two unique letters while JOHNSON has five unique letters 'JOHNS'.Theory: Brute force processing appears to be the way. Methodical processing and function usage can minimize code size. <a href = "http://code.google.com/codejam/contest/6304486/scoreboard#vf=1">GJam Kickstart solutions(C++,Python)</a>.

This Challenge is derived from <http://code.google.com/codejam/contest/6304486/dashboard#s=p0 GJam 2017 Kickstart Leader>. This is the first 61 small cases with no spaces in names.

<http://code.google.com/codejam Google Code Jam 2017 Qualifier> is March 7, 2017. Typically four challenges with small and large aspects with 27 hours to complete.

The GJam story is to determine the rightful leader.  The leader is the person whose name utilizes the most unique letters, spaces do not count, and if two or more people are tied then the leader is the one whom comes first alphabetically, with space preceding A, given a list of 100 or fewer names.

*Input:* [names], a cell array of names using only A thru Z; max 100 names

*Output:* [Leader], a string of the name of the leader

*Examples:* [names] [Leader]; {'ADAM' 'BOB' JOHNSON'} ['JOHNSON']

For the example the first two have three and two unique letters while JOHNSON has five unique letters 'JOHNS'.

*Theory:* Brute force processing appears to be the way. Methodical processing and function usage can minimize code size. <http://code.google.com/codejam/contest/6304486/scoreboard#vf=1 GJam Kickstart solutions(C++,Python)>.

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Problem 44078. GJam 2017 Kickstart: Leader (Small)

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Problem 44078. GJam 2017 Kickstart: Leader (Small)

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