Problem 44727. Let's Make A Deal: Criminal Minds

Created by J. S. Kowontan

Solve Later

{"relationships":[{"relationshipType":"http://schemas.mathworks.com/matlab/code/2013/relationships/document","targetMode":"","relationshipId":"rId1","target":"/matlab/document.xml"},{"relationshipType":"http://schemas.mathworks.com/matlab/code/2013/relationships/output","targetMode":"","relationshipId":"rId2","target":"/matlab/output.xml"}],"parts":[{"partUri":"/matlab/document.xml","relationship":[],"contentType":"application/vnd.mathworks.matlab.code.document+xml","content":"<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n<w:document xmlns:w=\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\"><w:body><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>The game of Let's Make A Deal proceeds as follows;</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>The player is given the choice of three doors: Behind one door is a car; behind the others, goats. The player picks a door, say No. 1, and the host, either immediately opens that door or opens another door, say No. 3, which might have the car or a goat. If the host opens door No. 3 and it has a goat behind it, he then offers the player the choice, \"Do you want to pick door No. 2?\"</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>The game play is guided by the following set of rules:</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"ListParagraph\"/><w:numPr><w:numId w:val=\"2\"/></w:numPr></w:pPr><w:r><w:t>The host can open any of the doors including that picked by the player.</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"ListParagraph\"/><w:numPr><w:numId w:val=\"2\"/></w:numPr></w:pPr><w:r><w:t>The host can open a door to reveal either a goat or the car.</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"ListParagraph\"/><w:numPr><w:numId w:val=\"2\"/></w:numPr></w:pPr><w:r><w:t>The host doesn't always offer the chance to switch between the originally chosen door and the closed doors.</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>In order to manipulate the game play, the host does not always (uniformly) randomly hide the car behind the doors. Instead, based on previous games statistics, the host determines the probability Pc.</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"code\"/></w:pPr><w:r><w:t><![CDATA[ Pc = [pc_1 pc_2 pc_3] pc_i is the probability of the host placing car behind door i.]]></w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>If the player initially picks door D, then the host's choice of which door to open is represented by a conditional probability matrix Ph</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"code\"/></w:pPr><w:r><w:t><![CDATA[ Ph = [ ph_11 ph_12 ph_13\n ph_21 ph_22 ph_23\n ph_31 ph_32 ph_33 ]]]></w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>In the above matrix, ph_ij represents the probability that the host opens door j given that the car is behind door i.</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>Interpreting the matrix in terms of the assumptions implies that all elements ph_ij of the conditional probability matrix can be nonzero with the constraint that</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"code\"/></w:pPr><w:r><w:t><![CDATA[ ph_i1 + ph_i2 + ph_i3 = 1 i.e. the host must always open a door to reveal the car or a goat.]]></w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>On the game show, the host places the car behind a door with probability Pc in order to manipulate the outcome. The player then choose door D and the host, Monty Hall, opens door H using the conditional probability Ph.</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>If the door H opened by the host has a goat behind it, what is the probability</w:t></w:r><w:r><w:t> </w:t></w:r><w:r><w:rPr><w:b/></w:rPr><w:t>Pws</w:t></w:r><w:r><w:t> that the player will win the car by switching the initial door choice to the door remaining?</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:rPr><w:b/></w:rPr><w:t>If switching option is not available (i.e. host always opens a door with the car behind it) return NaN.</w:t></w:r></w:p></w:body></w:document>"},{"partUri":"/matlab/output.xml","contentType":"text/xml","content":"<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"no\" ?><embeddedOutputs><metaData><evaluationState>manual</evaluationState><layoutState>code</layoutState><outputStatus>ready</outputStatus></metaData><outputArray type=\"array\"/><regionArray type=\"array\"/></embeddedOutputs>"}]}

The game of Let's Make A Deal proceeds as follows;The player is given the choice of three doors: Behind one door is a car; behind the others, goats. The player picks a door, say No. 1, and the host, either immediately opens that door or opens another door, say No. 3, which might have the car or a goat. If the host opens door No. 3 and it has a goat behind it, he then offers the player the choice, "Do you want to pick door No. 2?"The game play is guided by the following set of rules:<ol><li>The host can open any of the doors including that picked by the player.</li><li>The host can open a door to reveal either a goat or the car.</li><li>The host doesn't always offer the chance to switch between the originally chosen door and the closed doors.</li></ol>In order to manipulate the game play, the host does not always (uniformly) randomly hide the car behind the doors. Instead, based on previous games statistics, the host determines the probability Pc.<pre> Pc = [pc_1 pc_2 pc_3] pc_i is the probability of the host placing car behind door i. </pre>If the player initially picks door D, then the host's choice of which door to open is represented by a conditional probability matrix Ph<pre> Ph = [ ph_11 ph_12 ph_13
 ph_21 ph_22 ph_23
 ph_31 ph_32 ph_33 ]</pre>In the above matrix, ph_ij represents the probability that the host opens door j given that the car is behind door i.Interpreting the matrix in terms of the assumptions implies that all elements ph_ij of the conditional probability matrix can be nonzero with the constraint that<pre> ph_i1 + ph_i2 + ph_i3 = 1 i.e. the host must always open a door to reveal the car or a goat. </pre>On the game show, the host places the car behind a door with probability Pc in order to manipulate the outcome. The player then choose door D and the host, Monty Hall, opens door H using the conditional probability Ph.If the door H opened by the host has a goat behind it, what is the probability Pws that the player will win the car by switching the initial door choice to the door remaining?If switching option is not available (i.e. host always opens a door with the car behind it) return NaN.

The game of Let's Make A Deal proceeds as follows;

The player is given the choice of three doors: Behind one door is a car; behind the others, goats. The player picks a door, say No. 1, and the host, either immediately opens that door or opens another door, say No. 3, which might have the car or a goat. If the host opens door No. 3 and it has a goat behind it, he then offers the player the choice, "Do you want to pick door No. 2?"

The game play is guided by the following set of rules:

# The host can open any of the doors including that picked by the player.
# The host can open a door to reveal either a goat or the car.
# The host doesn't always offer the chance to switch between the originally chosen door and the closed doors.

In order to manipulate the game play, the host does not always (uniformly) randomly hide the car behind the doors. Instead, based on previous games statistics, the host determines the probability Pc.

Pc = [pc_1  pc_2  pc_3]   pc_i is the probability of the host placing car behind door i.

If the player initially picks door D, then the host's choice of which door to open is represented by a conditional probability matrix Ph

Ph = [ ph_11   ph_12   ph_13
          ph_21   ph_22   ph_23
          ph_31   ph_32   ph_33 ]

In the above matrix, ph_ij represents the probability that the host opens door j given that the car is behind door i.

Interpreting the matrix in terms of the assumptions implies that all elements ph_ij of the conditional probability matrix can be nonzero with the constraint that

ph_i1 + ph_i2 + ph_i3 = 1    i.e. the host must always open a door to reveal the car or a goat.

On the game show, the host places the car behind a door with probability Pc in order to manipulate the outcome. The player then choose door D and the host, Monty Hall, opens door H using the conditional probability Ph.

If the door H opened by the host has a goat behind it, what is the probability *Pws* that the player will win the car by switching the initial door choice to the door remaining?

*If switching option is not available (i.e. host always opens a door with the car behind it) return NaN.*

Solve

Solution Stats

2 Solutions
2 Solvers

Last Solution submitted on Feb 07, 2019

Last 200 Solutions

Problem Comments

1 Comment

1 Comment

Stephan Gesell on 5 Sep 2018

It seems like the test cases in section 2B are not right.

Problem Recent Solvers2

Problem Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Problem 44727. Let's Make A Deal: Criminal Minds

Solution Stats

Last 200 Solutions

Problem Comments

Problem Recent Solvers2

Suggested Problems

More from this Author18

Problem Tags

Community Treasure Hunt

Problem 44727. Let's Make A Deal: Criminal Minds

Solution Stats

Last 200 Solutions

Problem Comments

Problem Recent Solvers2

Suggested Problems

More from this Author18

Problem Tags

Community Treasure Hunt

Players