Given two numbers, m and n, find a matrix m x n where each element value is twice the value of the previous element. Starting from the position (1,1) with value equal to 1, until the position (m,n), following the direction from left to right in each row.
For example, for m=2 and n=3, one should get:
y = [1 2 4; 8 16 32].
Number of 1s in a binary string
750 Solvers
158 Solvers
512 Solvers
Matlab Basics - y as a function of x
221 Solvers
146 Solvers
Solution 1717118
Test 4 is wrong; y_correct should be [1; 2; 4]
I´m afraid all tests are correct. But thanks anyway!