Given a vector x, return a vector r that indicates the run length of any value in x. Each element in r shows how many times the corresponding element in x has appeared consecutively.
Example:
Input x = [5 3 3 1 0 9 9 4 4 4 4 5 1 2 2] Output r = [1 1 2 1 1 1 2 1 2 3 4 1 1 1 2]
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Problem Comments
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5 Comments
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2 older comments
Wenwu
on 4 Jan 2015
The first test case seems to be invalid answer. Please check it
Ned Gulley
on 6 Jan 2015
Hi Wenwu: Could you be more specific about what you think the problem is?
Carl Witthoft
on 9 Dec 2015
See FileExchange's seqle . (disclaimer: I'm the author)
hubert andre
on 13 Apr 2016
False exemple description
GEORGIOS BEKAS
on 14 Feb 2018
y=[];
for i = 1:length(delta)
test = max(delta(1:i));
maxsofar=max(delta(1:i-1));
test2=min(delta(1:i));
minsofar=min(delta(1:i-1));
if test == delta(i) && delta(i)~= maxsofar
y=[y,1];
elseif test2 == delta(i) && delta(i)~= minsofar
y=[y,-1];
else
y=[y,0];
end
end
this code despite its giving correct results it is rejected by the tests...
Solution Comments
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1 Comment
cool
on 24 Dec 2016
the 1st test suite seems not right.
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1 Comment
ABDELRAHMAN
on 28 Jan 2016
the sol of first test isn't correct
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