Given a point, P(x,y), find the distance from this point to a linear line.
INPUTS: x, y, A, B, C
OUTPUTS: d, the distance which of course should always be positive.
>>x=2; y=2; A=2; B=2; C=-4;
>>d = normalLen(x,y,A,B,C)
d = 1.4142
There is a mistake with the solution of Test #3. Ans should be 7.40. Please check.
note: this is the wrong formula (x=0;y=12345;A=0;B=1;C=0 should return 12345, not 1...)
Come on, Amitava - you don't need to game the solution.
Reverse the vector
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