The solution is a bit flawed as it works for the limited test cases in this problem.
A classic approach was to take intersection of factors of a and b, and take their product. This works perfectly on paper. However, the inbuilt intersect() function gives unique values discarding the repeated values, thus I was not able to use it.
Diagonal & Anti-Diagonal Matrix: Easy
Solving Quadratic Equations (Version 1)
Sum of series III
There are 10 types of people in the world
Remove All elements less than 5
Spiral Out - 01
Game of life - 01
Most Frequent Word - 01
Ugly numbers - 01
find nth even fibonacci number
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