Split a string into two strings, wherein the first string has all alphabetic letters and the second string has all the remaining characters, maintaining the same order as in the original string.
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2 Comments
Andrew Newell
on 18 Apr 2017
If test #1 is correct, there is something about this problem I don't understand:
length(Ly)+Length(Ln) = 23
length(LynLyn) = 25
yao gang
on 18 Jul 2017
yes,the space should all be in the remaining characters.
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1 Comment
Pavan Toraty
on 20 Nov 2013
Thank you Peter.
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1 Comment
Peter Wittenberg
on 1 Jan 2013
Why didn't I think of that? I used the relatively more elaborate regexp. I guess I didn't realize that isletter existed as a function. Well, that's why we work with Cody.
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