Write reduce function, that takes arguments and constantly folds results into next call argument, finally returning a value; i.e. for a binary operator Fb,

     reduce(Fb,{a,b,c},start_val) = F(F(F(start_val,a),b),c)

Same can be done for a n-ary operators.

Eg. reduce(@strcat,{'foo','bar','baz','bat'},' ') = reduce(@plus,{1,2,3,4},0) = 10 reduce(@max,{1,2,3,4},{5,6,7,8},5) = 8

Remember, we use cell arrays for passing arguments, not matrices!

Solution Stats

67 Solutions

20 Solvers

Last Solution submitted on May 26, 2026

Last 200 Solutions

Problem Comments

Solution Comments

Show comments
Loading...

Problem Recent Solvers20

Suggested Problems

More from this Author10

Problem Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!