Create n x 2n "mirror" matrix of this type:
For n = 2
m = [ 1 2 2 1
1 2 2 1 ]
For n = 3
m = [ 1 2 3 3 2 1
1 2 3 3 2 1
1 2 3 3 2 1 ]
This problem was fun. I was able to find a better way to solve beat my own solution. Not the best way though. But lot better.
Arrange Vector in descending order
We love vectorized solutions. Problem 1 : remove the row average.
Number of digits in an integer
Matrix to column conversion
Sum of series III
Sum of series IV
Sum of series VI
Sum of series II
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