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Zhuoran Han
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Why these two similar operations (a sparse matrix w/o transpose times a vector) take different time to finish?
n = 1e5; a = sprand(n,n,5/n); v = rand(n,1); tic; for i = 1:1e3, b = a*v; end; toc tic; for i = 1:1e3, c = a'*v; end; toc I...
environ 2 ans il y a | 2 réponses | 0
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réponsesdeleting row and column from very large Sparse matrix efficiently
This is an easy way to deal with boundary conditions in stiffness matrices, have you tried permutation? Suppose your original m...
plus de 3 ans il y a | 0